-[5z-(9z+1)]=1+(3z+0)

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Solution for -[5z-(9z+1)]=1+(3z+0) equation:


Simplifying
-1[5z + -1(9z + 1)] = 1 + (3z + 0)

Reorder the terms:
-1[5z + -1(1 + 9z)] = 1 + (3z + 0)
-1[5z + (1 * -1 + 9z * -1)] = 1 + (3z + 0)
-1[5z + (-1 + -9z)] = 1 + (3z + 0)

Reorder the terms:
-1[-1 + 5z + -9z] = 1 + (3z + 0)

Combine like terms: 5z + -9z = -4z
-1[-1 + -4z] = 1 + (3z + 0)
[-1 * -1 + -4z * -1] = 1 + (3z + 0)
[1 + 4z] = 1 + (3z + 0)

Reorder the terms:
1 + 4z = 1 + (0 + 3z)
Remove the zero:
1 + 4z = 1 + (3z)
1 + 4z = 1 + (3z)

Add '-1' to each side of the equation.
1 + -1 + 4z = 1 + -1 + (3z)

Combine like terms: 1 + -1 = 0
0 + 4z = 1 + -1 + (3z)
4z = 1 + -1 + (3z)

Combine like terms: 1 + -1 = 0
4z = 0 + (3z)
4z = (3z)

Solving
4z = (3z)

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '(-3z)' to each side of the equation.
4z + (-3z) = (3z) + (-3z)

Combine like terms: 4z + (-3z) = 1z
1z = (3z) + (-3z)

Combine like terms: (3z) + (-3z) = 0
1z = 0

Divide each side by '1'.
z = 0

Simplifying
z = 0

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